Consider the following proof exercise:
Show that \(x+0=0\) for every \(x \epsilon \mathbb{Z}\)
Proof:
Let \(x = [a,b]\) and recall that \(0 = [1,1]\).
Recall the definition of integer addition i.e. \([r,s] + [t,u] = [r+t, s+u]\).
So, \(x + 0 = [a, b] + [1, 1] = [a+1, b+1]\).
We need to show that \([a+1, b+1] = [a,b]\).
Recall that \(\mathbb{Z}\) is the set of equivalence classes of R where R is the relation on \(\mathbb{X}\) such that \((a,b)R(c,d)\) means \(a+d=b+c\) and \(\mathbb{X}\) is the set of ordered pairs \((a,b)\) of natural numbers.
\((a+1,b+1)R(a,b)\) since \(a+1+b = b+1+a\)
Thus, \([a+1,b+1]=[a,b]\) and the result holds.
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